代码: 全选
Here is the modified section of the code. You only need to replace the `// 5. If ckmode is "number"` section with the following block.
All code and comments are written in English as requested.
```javascript
// 5. If ckmode is "number"
else if (ckmode === "number") {
const ckvalue = obj.getAttribute("ckvalue");
if (ckvalue) {
const values = ckvalue.split(",").map(v => parseInt(v.trim()));
const presentNumbers = new Set(values);
// Coordinates for missing numbers (scale 0.7,0.7)
// Left side for odd numbers
const leftCoords = [
"translate(-120,-172) scale(0.7,0.7)",
"translate(-160,-160) scale(0.7,0.7)",
"translate(-172,-120) scale(0.7,0.7)",
"translate(-172,120) scale(0.7,0.7)",
"translate(-160,160) scale(0.7,0.7)",
"translate(-120,172) scale(0.7,0.7)"
];
// Right side for even numbers
const rightCoords = [
"translate(120,-172) scale(0.7,0.7)",
"translate(160,-160) scale(0.7,0.7)",
"translate(172,-120) scale(0.7,0.7)",
"translate(172,120) scale(0.7,0.7)",
"translate(160,160) scale(0.7,0.7)",
"translate(120,172) scale(0.7,0.7)"
];
let leftIndex = 0;
let rightIndex = 0;
// Step 5a: Find missing numbers (1-12) and place them on the sides
for (let num = 1; num <= 12; num++) {
if (!presentNumbers.has(num)) {
const tileIndex = num - 1;
if (tileElements[tileIndex]) {
if (num % 2 !== 0) {
// Odd number goes to the left
tileElements[tileIndex].setAttribute("transform", leftCoords[leftIndex]);
leftIndex++;
} else {
// Even number goes to the right
tileElements[tileIndex].setAttribute("transform", rightCoords[rightIndex]);
rightIndex++;
}
}
}
}
// Step 5b: Place the valid numbers provided in the input
values.forEach((val, positionIndex) => {
// Only process valid numbers (ignore 0)
if (val > 0 && val <= 12) {
const tileIndex = val - 1;
if (tileElements[tileIndex] && translateArray[positionIndex]) {
tileElements[tileIndex].setAttribute("transform", translateArray[positionIndex]);
}
}
});
}
}
```